144+25=c^2

Solution for 144+25=c^2 equation:

144+25=c^2

We move all terms to the left:

144+25-(c^2)=0

We add all the numbers together, and all the variables

-1c^2+169=0

a = -1; b = 0; c = +169;
Δ = b2-4ac
Δ = 02-4·(-1)·169
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-26}{2*-1}=\frac{-26}{-2}
=+13
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+26}{2*-1}=\frac{26}{-2}
=-13
$